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We fix a field F. Let R be a ring containing F.

by | Nov 28, 2023 | math

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We fix a field F. Let R be a ring containing F. We say that R is an algebra over F if addition and multiplication in R restrict to addition and multiplication in F and the element 1 is in F if the element 1 is in R. Let R be and algebra over F.1. Suppose that ?1 and ?2 are distinct homomorphisms F[x] –> R such that ?1(c) = ?2(c) = c for every c in the field. Show that ?1(x) does not equal ?2(x).2. If r is any element of R, show that there is a homomorphism ?: F[x] –> R such that ?(x) = r and ?1(c) = ?2(c) = ?1 for every c in F.3. Show that there is a bijection between the set R and the set of homomophisms ?: F[X] –> R such that ?1(c) = ?2(c) = c for every c in F

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