The altitude (in feet) of a model rocket t sec into a trial
flight is given by the following equation. s = f(t) = −4t3 + 24t2 +
3 (t ≥ 0) (a) Find an expression for the rocket’s velocity v at any
time t. v = −12t2+48t

Correct: Your answer is correct.

(b) Compute the rocket’s velocity when t = 0, 2, 4, and 6.

t = 0….___ft/sec

t = 2….___ ft/sec

t = 4……___ ft/sec

t = 6….___ ft/sec

Interpret your results.

The rocket climbs upward until it attains a maximum altitude 4
seconds into flight. After that, it descends until it hits the
ground.

(c) Using the results from the solution to part (b), find the
maximum altitude attained by the rocket. Hint: At its highest
point, the velocity of the rocket is zero. ________ ft